Tercera ley de Newton¶

Fig. 65 What is applying a stronger force? The right side object or the left side object?¶

(143)¶\[\vec{F}_{12}=-\vec{F}_{21}\]

Fuerzas internas y externas: Fuerza resultante¶

Fig. 66 Consider all the forces between objects that interact with each other¶

(144)¶\[\begin{split}\vec{F}_1 = -m_1 g\vec{j}+\vec{F}_{21}\\ \vec{F}_2 = -m_2 g\vec{j}+\vec{F}_{12}\end{split}\]

(145)¶\[\vec{F}_T=\vec{F}_1+\vec{F}_2=-m_1 g\vec{j}+\vec{F}_{21}-m_2 g\vec{j}+\vec{F}_{12}=-(m_1+m_2)g\vec{j}\]

I am writing an equation inline \(x=-i\hbar\psi=\hat{h}\psi\).

If the equation is by itself,

(146)¶\[-i\hbar\psi=\hat{h}\psi\]

I am going to add a figure

Fig. 67 Here is my figure caption!¶

:::{admonition,warning} This is also Markdown This text is standard Markdown :::

:::{admonition,note} This is also Markdown This text is standard Markdown :::

:::{admonition,tip} This is also Markdown This text is standard Markdown :::

There are many ways to write content in Jupyter Book. This short section covers a few tips for how to do so.

I am going to cite a reference [HdHPK14]

Now I am going to cite section escalares Sec. Magnitudes escalares

The Schrödinger equation is Eq. (195)

I am citing the figure: Fig. 102

I can start solving like this

(147)¶\[x=-2\pi\]

Some text needs to go between sidebars

(148)¶\[y=-log(e)\]

And at the end