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Teorema trabajo y energía

(204)\[\begin{split}W&=\int_{\vec{r}_0}^{\vec{r}_f}\vec{F}d\vec{r}=\int_{\vec{r}_0}^{\vec{r}_f}m\frac{d\vec{v}}{dt}d\vec{r} \underset{d\vec{r}=\vec{v}dt}{=}\int_{\vec{r}_0}^{\vec{r}_f}m\frac{d\vec{v}}{dt}\vec{v}dt\\ &\underset{dv^2=2\vec{v}\frac{d\vec{v}}{dt}dt}{=}\frac{1}{2}m\int_{\vec{v}_0}^{\vec{v}_f}{dv^2} =\frac{1}{2}mv_f^2-\frac{1}{2}mv_0^2\end{split}\]
(204)\[W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_0^2\]

Magnitudes escalares

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If the equation is by itself,

(205)\[-i\hbar\psi=\hat{h}\psi\]

I am going to add a figure

2_mecanica/trabajo_energia/../img/logo/logo_fisica.png

Fig. 105 Here is my figure caption!

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Magnitudes vectoriales

There are many ways to write content in Jupyter Book. This short section covers a few tips for how to do so.

I am going to cite a reference [HdHPK14]

Now I am going to cite section escalares Sec. Magnitudes escalares

The Schrödinger equation is Eq. (195)

I am citing the figure: Fig. 102

Unidades

Problemas y ejemplos resueltos

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(206)\[x=-2\pi\]

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We continue here

(207)\[y=-log(e)\]

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Bibliografía

Potencia Energía cinética